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Check if a N base number is Even or Odd

  • Difficulty Level : Medium
  • Last Updated : 24 Nov, 2021

Given a number num in base N, check whether it is even or odd.
Examples: 
 

Input: num = 10, N = 8
Output: Even
Explanation:
108 = 810, which is even

Input: num = 122, N = 5 
Output: Odd
Explanation:
1225 = 3710, which is odd

 

Approach: 
 

Below is the implementation of the above approach. 
 

C++




// C++ code to check if a Octal
// number is Even or Odd
#include <iostream>
using namespace std;
 
    // To return value of a char.
    int val(char c)
    {
        if (c >= '0' && c <= '9')
            return (int)c - '0';
        else
            return (int)c - 'A' + 10;
    }
 
    // Function to convert a
    // number from N base to decimal
    int toDeci(string str,
                      int base)
    {
        int len = str.length();
 
        // power of base
        int power = 1;
 
        int num = 0;
        int i;
 
        // Decimal equivalent is
        // str[len-1]*1 + str[len-1] *
        // base + str[len-1]*(base^2) + ...
        for (i = len - 1; i >= 0; i--) {
 
            // A digit in input number
            // must be less than
            // number's base
            if (val(str[i]) >= base) {
 
                cout << "Invalid Number";
                return -1;
            }
 
            num += val(str[i])* power;
            power = power * base;
        }
 
        return num;
    }
 
    // Returns true if n is even, else odd
     bool isEven(string num, int N)
    {
 
        int deci = toDeci(num, N);
 
        return (deci % 2 == 0);
    }
 
int main()
{
        string num = "11A";
        int N = 16;
 
        if (isEven(num, N)) {
            cout << "Even";
        }
        else {
            cout << "Odd";
        }
}
 
// This code is contributed by AnkitRai01

Java




// Java code to check if a Octal
// number is Even or Odd
 
import java.io.*;
 
class Main {
 
    // To return value of a char.
    static int val(char c)
    {
        if (c >= '0' && c <= '9')
            return (int)c - '0';
        else
            return (int)c - 'A' + 10;
    }
 
    // Function to convert a
    // number from N base to decimal
    static int toDeci(String str,
                      int base)
    {
        int len = str.length();
 
        // power of base
        int power = 1;
 
        int num = 0;
        int i;
 
        // Decimal equivalent is
        // str[len-1]*1 + str[len-1] *
        // base + str[len-1]*(base^2) + ...
        for (i = len - 1; i >= 0; i--) {
 
            // A digit in input number
            // must be less than
            // number's base
            if (val(str.charAt(i)) >= base) {
 
                System.out.println("Invalid Number");
                return -1;
            }
 
            num += val(str.charAt(i))
                   * power;
            power = power * base;
        }
 
        return num;
    }
 
    // Returns true if n is even, else odd
    public static boolean isEven(
        String num, int N)
    {
 
        int deci = toDeci(num, N);
 
        return (deci % 2 == 0);
    }
 
    // Driver code
    public static void main(String[] args)
    {
        String num = "11A";
        int N = 16;
 
        if (isEven(num, N)) {
            System.out.println("Even");
        }
        else {
            System.out.println("Odd");
        }
    }
}

Python3




# Python3 code to check if a Octal
# number is Even or Odd
 
# To return value of a char.
def val(c):
    if (ord(c) >= ord('0') and ord(c) <= ord('9')):
        return ord(c) - ord('0')
    else:
        return ord(c) - ord('A') + 10
 
# Function to convert a
# number from N base to decimal
def toDeci(str, base):
    Len = len(str)
 
    # power of base
    power = 1
 
    num = 0
 
    # Decimal equivaLent is
    # str[Len-1]*1 + str[Len-1] *
    # base + str[Len-1]*(base^2) + ...
    for i in range(Len-1, -1, -1):
 
        # A digit in input number
        # must be less than
        # number's base
        if (val(str[i]) >= base):
 
            print("Invalid Number")
            return -1
 
        num += val(str[i])*power
        power = power * base
 
    return num
 
# Returns true if n is even, else odd
def isEven(num, N):
 
    deci = toDeci(num, N)
 
    return (deci % 2 == 0)
 
# Driver code
if __name__ == '__main__':
    num = "11A"
    N = 16
 
    if (isEven(num, N)):
        print("Even")
    else:
        print("Odd")
 
# This code is contributed by mohit kumar 29

C#




// C# code to check if a Octal
// number is Even or Odd
using System;
 
class Gfg{
 
    // To return value of a char.
    static int val(char c)
    {
        if (c >= '0' && c <= '9')
            return (int)c - '0';
        else
            return (int)c - 'A' + 10;
    }
 
    // Function to convert a
    // number from N base to decimal
    static int toDeci(string str,int base_var)
    {
        int len = str.Length;
 
        // power of base
        int power = 1;
 
        int num = 0;
        int i;
 
        // Decimal equivalent is
        // str[len-1]*1 + str[len-1] *
        // base + str[len-1]*(base^2) + ...
        for (i = len - 1; i >= 0; i--) {
 
            // A digit in input number
            // must be less than
            // number's base
            if (val(str[i]) >= base_var) {
 
                Console.WriteLine("Invalid Number");
                return -1;
            }
 
            num += val(str[i])
                   * power;
            power = power * base_var;
        }
 
        return num;
    }
 
    // Returns true if n is even, else odd
    public static bool isEven(
        string num, int N)
    {
 
        int deci = toDeci(num, N);
 
        return (deci % 2 == 0);
    }
 
    // Driver code
    public static void Main(string[] args)
    {
        string num = "11A";
        int N = 16;
 
        if (isEven(num, N)) {
            Console.WriteLine("Even");
        }
        else {
            Console.WriteLine("Odd");
        }
    }
}
 
// This code is contributed by AnkitRai01

Javascript




<script>
 
// JavaScript code to check if a Octal
// number is Even or Odd
 
   // To return value of a char.
    function val(c)
    {
        if (c >= '0' && c <= '9')
            return c.charCodeAt() - '0'.charCodeAt();
        else
            return c.charCodeAt() - 'A'.charCodeAt() + 10;
    }
   
    // Function to convert a
    // number from N base to decimal
    function toDeci(str, base)
    {
        let len = str.length;
   
        // power of base
        let power = 1;
   
        let num = 0;
        let i;
   
        // Decimal equivalent is
        // str[len-1]*1 + str[len-1] *
        // base + str[len-1]*(base^2) + ...
        for (i = len - 1; i >= 0; i--) {
   
            // A digit in input number
            // must be less than
            // number's base
            if (val(str[i]) >= base) {
   
                 document.write("Invalid Number");
                return -1;
            }
   
            num += val(str[i])
                   * power;
            power = power * base;
        }
   
        return num;
    }
   
    // Returns true if n is even, else odd
    function isEven(num, N)
    {
   
        let deci = toDeci(num, N);
   
        return (deci % 2 == 0);
    }
 
// Driver Code
     
    let num = "11A";
        let N = 16;
   
        if (isEven(num, N)) {
            document.write("Even");
        }
        else {
            document.write("Odd");
        }
         
</script>
Output: 
Even

 

Time Complexity: O(len)

Auxiliary Space: O(1)


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