Check if a large number is divisible by 75 or not

• Last Updated : 18 Jun, 2021

Given a very large number in the form of a string, the task is to check if the number is divisible by 75 or not.
Examples:

```Input: N = 175
Output: No

Input: N = 100000000000000000754586672150
Output: Yes```

Approach: A number is divisible by 75 only if it is divisible by 3(if the sum of the digit is divisible by 3) and divisible by 25 (if the last two digit is divisible by 25) both.
Below is the implementation to check the given number is divisible by 75 or not.

C++

 `// C++ implementation to check the number``// is divisible by 75 or not``#include ``using` `namespace` `std;` `// check divisibleBy3``bool` `divisibleBy3(string number)``{``    ``// to store sum of Digit``    ``int` `sumOfDigit = 0;` `    ``// traversing through each digit``    ``for` `(``int` `i = 0; i < number.length(); i++)``        ``// summing up Digit``        ``sumOfDigit += number[i] - ``'0'``;` `    ``// check if sumOfDigit is divisibleBy3``    ``if` `(sumOfDigit % 3 == 0)``        ``return` `true``;` `    ``return` `false``;``}` `// check divisibleBy25``bool` `divisibleBy25(string number)``{``    ``// if a single digit number``    ``if` `(number.length() < 2)``        ``return` `false``;` `    ``// length of the number``    ``int` `length = number.length();` `    ``// taking the last two digit``    ``int` `lastTwo = (number[length - 2] - ``'0'``) * 10``                  ``+ (number[length - 1] - ``'0'``);` `    ``// checking if the lastTwo digit is divisibleBy25``    ``if` `(lastTwo % 25 == 0)``        ``return` `true``;` `    ``return` `false``;``}` `// Function to check divisibleBy75 or not``bool` `divisibleBy75(string number)``{` `    ``// check if divisibleBy3 and divisibleBy25``    ``if` `(divisibleBy3(number) && divisibleBy25(number))``        ``return` `true``;` `    ``return` `false``;``}` `// Drivers code``int` `main()``{``    ``string number = ``"754586672150"``;` `    ``// divisible``    ``bool` `divisible = divisibleBy75(number);` `    ``// if divisibleBy75``    ``if` `(divisible)``        ``cout << ``"Yes"``;``    ``else``        ``cout << ``"No"``;` `    ``return` `0;``}`

Java

 `// Java implementation to check the number``// is divisible by 75 or not` `import` `java.io.*;` `class` `GFG {`  `// check divisibleBy3``static` `boolean` `divisibleBy3(String number)``{``    ``// to store sum of Digit``    ``int` `sumOfDigit = ``0``;` `    ``// traversing through each digit``    ``for` `(``int` `i = ``0``; i < number.length(); i++)``        ``// summing up Digit``        ``sumOfDigit += number.charAt(i) - ``'0'``;` `    ``// check if sumOfDigit is divisibleBy3``    ``if` `(sumOfDigit % ``3` `== ``0``)``        ``return` `true``;` `    ``return` `false``;``}` `// check divisibleBy25``static`  `boolean` `divisibleBy25(String number)``{``    ``// if a single digit number``    ``if` `(number.length() < ``2``)``        ``return` `false``;` `    ``// length of the number``    ``int` `length = number.length();` `    ``// taking the last two digit``    ``int` `lastTwo = (number.charAt(length - ``2``) - ``'0'``) * ``10``                ``+ (number.charAt(length - ``1``) - ``'0'``);` `    ``// checking if the lastTwo digit is divisibleBy25``    ``if` `(lastTwo % ``25` `== ``0``)``        ``return` `true``;` `    ``return` `false``;``}` `// Function to check divisibleBy75 or not``static` `boolean` `divisibleBy75(String number)``{` `    ``// check if divisibleBy3 and divisibleBy25``    ``if` `(divisibleBy3(number) && divisibleBy25(number))``        ``return` `true``;` `    ``return` `false``;``}` `// Drivers code` `    ``public` `static` `void` `main (String[] args) {``    ``String number = ``"754586672150"``;` `    ``// divisible``    ``boolean` `divisible = divisibleBy75(number);` `    ``// if divisibleBy75``    ``if` `(divisible)``        ``System.out.println( ``"Yes"``);``    ``else``        ``System.out.println( ``"No"``);``    ``}``}``// This code is contributed``// by inder_verma..`

Python3

 `# Python 3 implementation to check the``# number is divisible by 75 or not` `# check divisibleBy3``def` `divisibleBy3(number):``    ` `    ``# to store sum of Digit``    ``sumOfDigit ``=` `0` `    ``# traversing through each digit``    ``for` `i ``in` `range``(``0``, ``len``(number), ``1``):``        ` `        ``# summing up Digit``        ``sumOfDigit ``+``=` `ord``(number[i]) ``-` `ord``(``'0'``)` `    ``# check if sumOfDigit is divisibleBy3``    ``if` `(sumOfDigit ``%` `3` `=``=` `0``):``        ``return` `True` `    ``return` `False` `# check divisibleBy25``def` `divisibleBy25(number):``    ` `    ``# if a single digit number``    ``if` `(``len``(number) < ``2``):``        ``return` `False` `    ``# length of the number``    ``length ``=` `len``(number)` `    ``# taking the last two digit``    ``lastTwo ``=` `((``ord``(number[length ``-` `2``]) ``-``                ``ord``(``'0'``)) ``*` `10` `+``               ``(``ord``(number[length ``-` `1``]) ``-` `ord``(``'0'``)))` `    ``# checking if the lastTwo digit``    ``# is divisibleBy25``    ``if` `(lastTwo ``%` `25` `=``=` `0``):``        ``return` `True` `    ``return` `False` `# Function to check divisibleBy75 or not``def` `divisibleBy75(number):``    ` `    ``# check if divisibleBy3 and divisibleBy25``    ``if` `(divisibleBy3(number) ``and``        ``divisibleBy25(number)):``        ``return` `True` `    ``return` `False` `# Driver Code``if` `__name__ ``=``=` `'__main__'``:``    ``number ``=` `"754586672150"` `    ``# divisible``    ``divisible ``=` `divisibleBy75(number)` `    ``# if divisibleBy75``    ``if` `(divisible):``        ``print``(``"Yes"``)``    ``else``:``        ``print``(``"No"``)` `# This code is contributed by``# Surendra_Gangwar`

C#

 `// C# implementation to check the number``// is divisible by 75 or not``using` `System;` `class` `GFG``{` `// check divisibleBy3``static` `bool` `divisibleBy3(``string` `number)``{``    ``// to store sum of Digit``    ``int` `sumOfDigit = 0;` `    ``// traversing through each digit``    ``for` `(``int` `i = 0; i < number.Length; i++)``    ` `        ``// summing up Digit``        ``sumOfDigit += number[i] - ``'0'``;` `    ``// check if sumOfDigit is divisibleBy3``    ``if` `(sumOfDigit % 3 == 0)``        ``return` `true``;` `    ``return` `false``;``}` `// check divisibleBy25``static` `bool` `divisibleBy25(``string` `number)``{``    ``// if a single digit number``    ``if` `(number.Length < 2)``        ``return` `false``;` `    ``// length of the number``    ``int` `length = number.Length;` `    ``// taking the last two digit``    ``int` `lastTwo = (number[length - 2] - ``'0'``) * 10 +``                  ``(number[length - 1] - ``'0'``);` `    ``// checking if the lastTwo digit``    ``// is divisibleBy25``    ``if` `(lastTwo % 25 == 0)``        ``return` `true``;` `    ``return` `false``;``}` `// Function to check divisibleBy75 or not``static` `bool` `divisibleBy75(``string` `number)``{` `    ``// check if divisibleBy3 and divisibleBy25``    ``if` `(divisibleBy3(number) && divisibleBy25(number))``        ``return` `true``;` `    ``return` `false``;``}` `// Driver Code``public` `static` `void` `Main ()``{``    ``string` `number = ``"754586672150"``;``    ` `    ``// divisible``    ``bool` `divisible = divisibleBy75(number);``    ` `    ``// if divisibleBy75``    ``if` `(divisible)``        ``Console.WriteLine( ``"Yes"``);``    ``else``        ``Console.WriteLine( ``"No"``);``}``}` `// This code is contributed``// by inder_verma..`

PHP

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Javascript

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Output:
`No`

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