Check if binary representation of a number is palindrome

Given an integer ‘x’, write a C function that returns true if binary representation of x is palindrome else return false.

For example a numbers with binary representation as 10..01 is palindrome and number with binary representation as 10..00 is not palindrome.

The idea is similar to checking a string is palindrome or not. We start from leftmost and rightmost bits and compare bits one by one. If we find a mismatch, then return false.

Algorithm:
isPalindrome(x)
1) Find number of bits in x using sizeof() operator.
2) Initialize left and right positions as 1 and n respectively.
3) Do following while left ‘l’ is smaller than right ‘r’.
..…..a) If bit at position ‘l’ is not same as bit at position ‘r’, then return false.
..…..b) Increment ‘l’ and decrement ‘r’, i.e., do l++ and r–-.
4) If we reach here, it means we didn’t find a mismatching bit.

To find the bit at a given position, we can use the idea similar to this post. The expression “x & (1 << (k-1))” gives us non-zero value if bit at k’th position from right is set and gives a zero value if if k’th bit is not set.



Following is the implementation of the above algorithm.

C/C++

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// C++ Program to Check if binary representation
// of a number is palindrome
#include<iostream>
using namespace std;
  
// This function returns true if k'th bit in x 
// is set (or 1). For example if x (0010) is 2 
// and k is 2, then it returns true
bool isKthBitSet(unsigned int x, unsigned int k)
{
    return (x & (1 << (k - 1))) ? true : false;
}
  
// This function returns true if binary 
// representation of x is palindrome.
// For example (1000...001) is paldindrome
bool isPalindrome(unsigned int x)
{
    int l = 1; // Initialize left position
    int r = sizeof(unsigned int) * 8; // initialize right position
  
    // One by one compare bits
    while (l < r)
    {
        if (isKthBitSet(x, l) != isKthBitSet(x, r))
            return false;
        l++; r--;
    }
    return true;
}
  
// Driver Code
int main()
{
    unsigned int x = 1 << 15 + 1 << 16;
    cout << isPalindrome(x) << endl;
    x = 1 << 31 + 1;
    cout << isPalindrome(x) << endl;
    return 0;
}

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# python 3 Program to Check if binary representation 


# of a number is palindrome 


import sys 


# This function returns true if k'th bit in x  


# is set (or 1). For example if x (0010) is 2  


# and k is 2, then it returns true 


def isKthBitSet(x, k): 


    if ((x & (1 << (k - 1))) !=0): 


        return True


    else: 


        return False


  


# This function returns true if binary  


# representation of x is palindrome. 


# For example (1000...001) is paldindrome 


def isPalindrome(x): 


    l = 1 # Initialize left position 


    r = 2 * 8 # initialize right position 


  


    # One by one compare bits 


    while (l < r): 


        if (isKthBitSet(x, l) != isKthBitSet(x, r)): 


            return False


        l += 1


        r -= 1


      


    return True


  


# Driver Code 


if __name__ =='__main__': 


    x = 1 << 15 + 1 << 16


    print(int(isPalindrome(x))) 


    x = 1 << 31 + 1


    print(int(isPalindrome(x))) 


  


# This code is contributed by 


# Surendra_Gangwar 



















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PHP














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<?php 


// PHP Program to Check if binary representation 


// of a number is palindrome 


  


// This function returns true if k'th bit in x  


// is set (or 1). For example if x (0010) is 2  


// and k is 2, then it returns true 


function isKthBitSet($x, $k) 


{ 


    return ($x & (1 << ($k - 1))) ? true : false; 


} 


  


// This function returns true if binary  


// representation of x is palindrome.  


// For example (1000...001) is paldindrome 


function isPalindrome($x) 


{ 


    $l = 1; // Initialize left position 


    $r = sizeof(4) * 8; // initialize right position 


  


    // One by one compare bits 


    while ($l < $r) 


    { 


        if (isKthBitSet($x, $l) != isKthBitSet($x, $r)) 


            return false; 


        $l++;  


        $r--; 


    } 


    return true; 


} 


  


// Driver Code 


$x = 1 << 15 + 1 << 16; 


echo isPalindrome($x), "\n"; 


$x = 1 << 31 + 1; 


echo isPalindrome($x), "\n"; 


  


// This code is contributed by ajit. 


?> 



















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Output: 


1
1


This article is contributed by Saurabh Gupta. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.



          
          
          
          

            

    

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