Check Armstrong Number in PL/SQL
Given a number x, determine whether the given number is Armstrong number or not. A positive integer of n digits is called an Armstrong number of order n (order is number of digits) if.
abcd... = pow(a, n) + pow(b, n) + pow(c, n) + pow(d, n) + ....
Example:
Input : 153
Output : Yes
153 is an Armstrong number.
1*1*1 + 5*5*5 + 3*3*3 = 153
Input : 120
Output : No
120 is not a Armstrong number.
1*1*1 + 2*2*2 + 0*0*0 = 9
Input : 1253
Output : No
1253 is not a Armstrong Number
1*1*1*1 + 2*2*2*2 + 5*5*5*5 + 3*3*3*3 = 723
Input : 1634
Output : Yes
1*1*1*1 + 6*6*6*6 + 3*3*3*3 + 4*4*4*4 = 1634
declare
n number:=1634;
s number:=0;
r number;
len number;
m number;
begin
m := n;
len := length(to_char(n));
while n>0
loop
r := mod(n , 10);
s := s + power(r , len);
n := trunc(n / 10);
end loop;
if m = s
then
dbms_output.put_line( 'yes' );
else
dbms_output.put_line( 'no' );
end if;
end ;
|
output:
Yes
Last Updated :
04 Jul, 2018
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