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Calculation in parent and child process using fork()
  • Difficulty Level : Easy
  • Last Updated : 29 Aug, 2017

Write a program to find sum of even numbers in parent process and sum of odd numbers in child process.

Examples:

Input : 1, 2, 3, 4, 5 

Output :
Parent process 
Sum of even no. is 6
Child process 
Sum of odd no. is 10

Explanation: Here, we had used fork() function to create two processes one child and one parent process.

  • For child process fork() returns 0 so we can calculate sum of all odd numbers in child process.
  • fork() returns value greater than 0 for parent process so we can calculate sum



  • for all even numbers there by just simply checking the value returned by fork().




// C++ program to demonstrate calculation in parent and
// child processes using fork()
#include <iostream>
#include <unistd.h>
using namespace std;
  
// Driver code
int main()
{
    int a[10] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
    int sumOdd = 0, sumEven = 0, n, i;
    n = fork();
  
    // Checking if n is not 0
    if (n > 0) {
        for (i = 0; i < 10; i++) {
            if (a[i] % 2 == 0)
                sumEven = sumEven + a[i];
        }
        cout << "Parent process \n";
        cout << "Sum of even no. is " << sumEven << endl;
    }
  
    // If n is 0 i.e. we are in child process
    else {
        for (i = 0; i < 10; i++) {
            if (a[i] % 2 != 0)
                sumOdd = sumOdd + a[i];
        }
        cout << "Child process \n";
        cout << "\nSum of odd no. is " << sumOdd << endl;
    }
    return 0;
}

Output:

Parent process 
Sum of even no. is 30
Child process 
Sum of odd no. is 25

This article is contributed by Pushpanjali Chauhan. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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