# Calculation in parent and child process using fork()

Write a program to find sum of even numbers in parent process and sum of odd numbers in child process.

Examples:

```Input : 1, 2, 3, 4, 5

Output :
Parent process
Sum of even no. is 6
Child process
Sum of odd no. is 10
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Explanation: Here, we had used fork() function to create two processes one child and one parent process.

• For child process fork() returns 0 so we can calculate sum of all odd numbers in child process.
• fork() returns value greater than 0 for parent process so we can calculate sum

• for all even numbers there by just simply checking the value returned by fork().

 `// C++ program to demonstrate calculation in parent and ` `// child processes using fork() ` `#include ` `#include ` `using` `namespace` `std; ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``int` `a = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }; ` `    ``int` `sumOdd = 0, sumEven = 0, n, i; ` `    ``n = fork(); ` ` `  `    ``// Checking if n is not 0 ` `    ``if` `(n > 0) { ` `        ``for` `(i = 0; i < 10; i++) { ` `            ``if` `(a[i] % 2 == 0) ` `                ``sumEven = sumEven + a[i]; ` `        ``} ` `        ``cout << ``"Parent process \n"``; ` `        ``cout << ``"Sum of even no. is "` `<< sumEven << endl; ` `    ``} ` ` `  `    ``// If n is 0 i.e. we are in child process ` `    ``else` `{ ` `        ``for` `(i = 0; i < 10; i++) { ` `            ``if` `(a[i] % 2 != 0) ` `                ``sumOdd = sumOdd + a[i]; ` `        ``} ` `        ``cout << ``"Child process \n"``; ` `        ``cout << ``"\nSum of odd no. is "` `<< sumOdd << endl; ` `    ``} ` `    ``return` `0; ` `} `

Output:

```Parent process
Sum of even no. is 30
Child process
Sum of odd no. is 25
```

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