# Calculate the total fine to be collected

• Difficulty Level : Easy
• Last Updated : 01 Sep, 2022

Given a date and an array of integer containing the numbers of the cars traveling on that date(an integer), the task is to calculate the total fine collected based on the following rules:

• Odd numbered cars can travel on only odd dates.
• Even numbered cars on only even dates.
• Otherwise a car would be fined 250 Rs.

Examples:

```Input: car_num[] = {3, 4, 1, 2}, date = 15
Output: 500
Car with numbers '4' and '2' will be fined
250 each.

Input: car_num[] = {1, 2, 3} , date = 16
Output: 500
Car with numbers '1' and '3' will be fined
250 each.```

Approach:

1. Start traversing the given array.
2. Check if the current car number and date don’t match i.e. one is even and other is odd or vice-versa.
3. If not matched charge the fine on that car number. Else, not.
4. Print the total fine.

Below is the implementation of above approach:

## C++

 `// C++ implementation to calculate``// the total fine collected``#include ``using` `namespace` `std;` `// function to calculate the total fine collected``int` `totFine(``int` `car_num[], ``int` `n, ``int` `date, ``int` `fine)``{``    ``int` `tot_fine = 0;` `    ``// traverse the array elements``    ``for` `(``int` `i = 0; i < n; i++)` `        ``// if both car no and date are odd or``        ``// both are even, then statement``        ``// evaluates to true``        ``if` `(((car_num[i] ^ date) & 1) == 1)``            ``tot_fine += fine;` `    ``// required total fine``    ``return` `tot_fine;``}` `// Driver program to test above``int` `main()``{``    ``int` `car_num[] = { 3, 4, 1, 2 };``    ``int` `n = ``sizeof``(car_num) / ``sizeof``(car_num);``    ``int` `date = 15, fine = 250;` `    ``cout << totFine(car_num, n, date, fine);` `    ``return` `0;``}`

## Java

 `// Java implementation to calculate``// the total fine collected``class` `GFG``{` `// function to calculate``// the total fine collected``static` `int` `totFine(``int` `car_num[], ``int` `n,``                   ``int` `date, ``int` `fine)``{``int` `tot_fine = ``0``;` `// traverse the array elements``for` `(``int` `i = ``0``; i < n; i++)` `    ``// if both car no and date``    ``// are odd or both are even,``    ``// then statement evaluates to true``    ``if` `(((car_num[i] ^ date) & ``1``) == ``1``)``        ``tot_fine += fine;` `// required total fine``return` `tot_fine;``}` `// Driver Code``public` `static` `void` `main(String[] args)``{``    ``int` `car_num[] = { ``3``, ``4``, ``1``, ``2` `};``    ``int` `n = car_num.length;``    ``int` `date = ``15``, fine = ``250``;` `    ``System.out.println(totFine(car_num, n,``                               ``date, fine));``}``}` `// This code is contributed``// by ChitraNayal`

## Python 3

 `# Python 3 program to calculate``# the total fine collected` `# function to calculate the total fine collected``def` `totFine(car_num, n, date, fine) :` `    ``tot_fine ``=` `0` `    ``# traverse the array elements``    ``for` `i ``in` `range``(n) :``        ` `        ``# if both car no and date are odd or``        ``# both are even, then statement``        ``# evaluates to true``        ``if` `(((car_num[i] ^ date) & ``1``) ``=``=` `1` `):``            ``tot_fine ``+``=` `fine` `    ``# required total fine``    ``return` `tot_fine` `# Driver Program``if` `__name__ ``=``=` `"__main__"` `:` `    ``car_num ``=` `[ ``3``, ``4``, ``1``, ``2` `]``    ``n ``=` `len``(car_num)``    ``date, fine ``=` `15``, ``250` `    ``# function calling``    ``print``(totFine(car_num, n, date, fine))``            ` `# This code is contributed by ANKITRAI1`

## C#

 `// C# implementation to calculate``// the total fine collected``using` `System;` `class` `GFG``{` `// function to calculate the``// total fine collected``static` `int` `totFine(``int``[] car_num, ``int` `n,``                   ``int` `date, ``int` `fine)``{``int` `tot_fine = 0;` `// traverse the array elements``for` `(``int` `i = 0; i < n; i++)` `    ``// if both car no and date``    ``// are odd or both are even,``    ``// then statement evaluates to true``    ``if` `(((car_num[i] ^ date) & 1) == 1)``        ``tot_fine += fine;` `// required total fine``return` `tot_fine;``}` `// Driver Code``public` `static` `void` `Main()``{``    ``int``[] car_num = { 3, 4, 1, 2 };``    ``int` `n = car_num.Length;``    ``int` `date = 15, fine = 250;` `    ``Console.Write(totFine(car_num, n,``                          ``date, fine));``}``}` `// This code is contributed``// by ChitraNayal`

## PHP

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## Javascript

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Output

`500`

Complexity Analysis:

• Time complexity: O(n)
• Auxiliary Space: O(1)

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