Skip to content
Related Articles

Related Articles

Calculate ratio of area of a triangle inscribed in an Ellipse and the triangle formed by corresponding points on auxiliary circle
  • Last Updated : 16 Apr, 2021

Given two integers A and B representing the lengths of semi-major and semi-minor axes of an ellipse, the task is to calculate the ratio of any triangle inscribed in the ellipse and that of the triangle formed by the corresponding points on its auxiliary circle.

Examples:

Input: A = 1, B = 2
Output: 2
Explanation: Ratio = B / A = 2 / 1 = 2

Input: A = 2, B = 3
Output: 1.5

 

Approach:



The idea is based on the following mathematical formula:

  • Let the 3 points on the ellipse be P(a cosX, b sinX), Q(a cosY, b sinY), R(a cosZ, b sinZ).
  • Therefore, the corresponding points on the auxiliary circles are A(a cosX, a sinX), B(a cosY, a sinY), C(a cosZ, a sinZ). 
  • Now, using the formula to calculate the area of triangle using the given points of the triangle.

Area(PQR) / Area(ABC) = b / a

Follow the steps below to solve the problem:

Below is the implementation of the above approach:

C++




// C++ program for the above approach
#include <bits/stdc++.h>
using namespace std;
 
// Function to calculate ratio of a
// triangle inscribed in an ellipse to
// the triangle on the auxiliary circle
void triangleArea(int a, int b)
{
    // Stores the ratio of the
    // semi-major to semi-minor axes
    double ratio = (double)b / a;
 
    // Print the ratio
    cout << ratio;
}
 
// Driver Code
int main()
{
    int a = 1, b = 2;
    triangleArea(a, b);
 
    return 0;
}

Java




// Java program for the above approach
class GFG{
  
// Function to calculate ratio of a
// triangle inscribed in an ellipse to
// the triangle on the auxiliary circle
static void triangleArea(int a, int b)
{
     
    // Stores the ratio of the
    // semi-major to semi-minor axes
    double ratio = (double)b / a;
 
    // Print the ratio
    System.out.println(ratio);
}
 
// Driver Code
public static void main(String args[])
{
    int a = 1, b = 2;
     
    triangleArea(a, b);
}
}
 
// This code is contributed by AnkThon

Python3




# Python3 program for the above approach
 
# Function to calculate ratio of a
# triangle inscribed in an ellipse to
# the triangle on the auxiliary circle
def triangleArea(a, b):
 
    # Stores the ratio of the
    # semi-major to semi-minor axes
    ratio = b / a
 
    # Print the ratio
    print(ratio)
 
# Driver Code
if __name__ == "__main__" :
 
    a = 1
    b = 2
     
    triangleArea(a, b)
 
# This code is contributed by AnkThon

C#




// C# program for the above approach
using System;
using System.Collections.Generic;
 
class GFG{
  
// Function to calculate ratio of a
// triangle inscribed in an ellipse to
// the triangle on the auxiliary circle
static void triangleArea(int a, int b)
{
     
    // Stores the ratio of the
    // semi-major to semi-minor axes
    double ratio = (double)b / a;
 
    // Print the ratio
    Console.WriteLine(ratio);
}
 
// Driver Code
public static void Main()
{
    int a = 1, b = 2;
     
    triangleArea(a, b);
}
}
 
// This code is contributed by bgangwar59

Javascript




<script>
 
// JavaScript program for the above approach
 
// Function to calculate ratio of a
// triangle inscribed in an ellipse to
// the triangle on the auxiliary circle
function triangleArea(a, b){
 
    // Stores the ratio of the
    // semi-major to semi-minor axes
    ratio = b / a
 
    // Print the ratio
    document.write(ratio)
}
 
// Driver Code
var a = 1
var b = 2
     
triangleArea(a, b)
 
// This code is contributed by AnkThon
 
</script>
Output: 
2

 

Time Complexity: O(1)
Auxiliary Space: O(1)

 

Attention reader! Don’t stop learning now. Get hold of all the important mathematical concepts for competitive programming with the Essential Maths for CP Course at a student-friendly price. To complete your preparation from learning a language to DS Algo and many more,  please refer Complete Interview Preparation Course.

My Personal Notes arrow_drop_up
Recommended Articles
Page :