# Calculate n + nn + nnn + … + n(m times) in Python

• Last Updated : 05 Nov, 2019

The program is to find a mathematical series, where we need to accept the value of n and m. n is the base number and m is the number of times till which the series run.

Examples:

```Input : 2 + 22 + 222 + 2222 + 22222
Output : 24690

Input : 12 + 1212 + 121212
Output : 122436
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

We first convert the numbers into string format and concatenate them regularly. Later, we convert them back to integer and add them upto mth term. as shown in the following program.

 `# Python program to sum the given series`` ` `# Returns sum of n + nn + nnn + .... (m times)``def` `Series(n, m):`` ` `    ``# Converting the number to string``    ``str_n ``=` `str``(n)`` ` `    ``# Initializing result as number and string``    ``sums ``=` `n``    ``sum_str ``=` `str``(n)`` ` `    ``# Adding remaining terms``    ``for` `i ``in` `range``(``1``, m):``        ` `        ``# Concatenating the string making n, nn, nnn...``        ``sum_str ``=` `sum_str ``+` `str_n``         ` `        ``# Before adding converting back to integer``        ``sums ``=` `sums ``+` `int``(sum_str)`` ` `    ``return` `sums`` ` `# Driver Code``n ``=` `2``m ``=` `5``total ``=` `Series(n, m)``print``(total)`

Output:

```24690
```
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