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C++ | Virtual Functions | Question 7

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  • Difficulty Level : Medium
  • Last Updated : 28 Jun, 2021

using namespace std;
class Base
    virtual void show() = 0;
class Derived: public Base
    void show() { cout<<"In Derived \n"; }
int main(void)
    Derived d;
    Base &br = d;;
    return 0;

(A) Compiler Error in line “Base &br = d;”
(B) Empty Output
(C) In Derived

Answer: (C)

Explanation: Please refer Pure Virtual Functions and Abstract Classes in C++

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