C++ | Virtual Functions | Question 3
Output of following program
#include<iostream>using namespace std; class Base{public: virtual void show() { cout<<" In Base \n"; }}; class Derived: public Base{public: void show() { cout<<"In Derived \n"; }}; int main(void){ Base *bp, b; Derived d; bp = &d; bp->show(); bp = &b; bp->show(); return 0;} |
(A)
In Base In Base
(B)
In Base In Derived
(C)
In Derived In Derived
(D)
In Derived In Base
Answer: (D)
Explanation: Initially base pointer points to a derived class object. Later it points to base class object,
Quiz of this Question
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