C++ | Virtual Functions | Question 3

Output of following program

#include<iostream> 
using namespace std; 
  
class Base 
{ 
public: 
    virtual void show() { cout<<" In Base \n"; } 
}; 
  
class Derived: public Base 
{ 
public: 
    void show() { cout<<"In Derived \n"; } 
}; 
  
int main(void) 
{ 
    Base *bp, b; 
    Derived d; 
    bp = &d; 
    bp->show(); 
    bp = &b; 
    bp->show(); 
    return 0; 
} 

(A)

In Base 
In Base

(B)

In Base 
In Derived

(C)

In Derived
In Derived

(D)

In Derived
In Base

Answer: (D)

Explanation: Initially base pointer points to a derived class object. Later it points to base class object,

Quiz of this Question

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