Output of following program
#include<iostream>
using namespace std;
class Base
{
public:
virtual void show() { cout<<" In Base \n"; }
};
class Derived: public Base
{
public:
void show() { cout<<"In Derived \n"; }
};
int main(void)
{
Base *bp, b;
Derived d;
bp = &d;
bp->show();
bp = &b;
bp->show();
return 0;
}
|
(A)
In Base
In Base
(B)
In Base
In Derived
(C)
In Derived
In Derived
(D)
In Derived
In Base
Answer: (D)
Explanation: Initially base pointer points to a derived class object. Later it points to base class object,
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Last Updated :
28 Jun, 2021
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