C++ | Virtual Functions | Question 10

#include<iostream> 
using namespace std; 
class Base  { 
public: 
    Base()    { cout<<"Constructor: Base"<<endl; } 
    virtual ~Base()   { cout<<"Destructor : Base"<<endl; } 
}; 
class Derived: public Base { 
public: 
    Derived()   { cout<<"Constructor: Derived"<<endl; } 
    ~Derived()  { cout<<"Destructor : Derived"<<endl; } 
}; 
int main()  { 
    Base *Var = new Derived(); 
    delete Var; 
    return 0; 
} 

(A)

Constructor: Base
Constructor: Derived
Destructor : Derived
Destructor : Base

(B)

Constructor: Base
Constructor: Derived
Destructor : Base

(C)

Constructor: Base
Constructor: Derived
Destructor : Derived

(D)

Constructor: Derived
Destructor : Derived

Answer: (A)

Explanation: Since the destructor is vitrual, the derived class destructor is called which in turn calls base class destructor.

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