C++ | Virtual Functions | Question 10
#include<iostream>using namespace std;class Base {public: Base() { cout<<"Constructor: Base"<<endl; } virtual ~Base() { cout<<"Destructor : Base"<<endl; }};class Derived: public Base {public: Derived() { cout<<"Constructor: Derived"<<endl; } ~Derived() { cout<<"Destructor : Derived"<<endl; }};int main() { Base *Var = new Derived(); delete Var; return 0;} |
(A)
Constructor: Base Constructor: Derived Destructor : Derived Destructor : Base
(B)
Constructor: Base Constructor: Derived Destructor : Base
(C)
Constructor: Base Constructor: Derived Destructor : Derived
(D)
Constructor: Derived Destructor : Derived
Answer: (A)
Explanation: Since the destructor is vitrual, the derived class destructor is called which in turn calls base class destructor.
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