C | Variable Declaration and Scope | Question 6

Output?

#include <stdio.h> 
int main() 
{ 
  int x = 1, y = 2, z = 3; 
  printf(" x = %d, y = %d, z = %d \n", x, y, z); 
  { 
       int x = 10; 
       float y = 20; 
       printf(" x = %d, y = %f, z = %d \n", x, y, z); 
       { 
             int z = 100; 
             printf(" x = %d, y = %f, z = %d \n", x, y, z); 
       } 
  } 
  return 0; 
} 

(A)

 x = 1, y = 2, z = 3
 x = 10, y = 20.000000, z = 3
 x = 1, y = 2, z = 100

(B) Compiler Error
(C)

 x = 1, y = 2, z = 3
 x = 10, y = 20.000000, z = 3
 x = 10, y = 20.000000, z = 100

(D)

 x = 1, y = 2, z = 3
 x = 1, y = 2, z = 3
 x = 1, y = 2, z = 3

Answer: (C)

Explanation: See Scope rules in C

Quiz of this Question

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