C | Variable Declaration and Scope | Question 6

Output?

filter_none

edit
close

play_arrow

link
brightness_4
code

#include <stdio.h>
int main()
{
  int x = 1, y = 2, z = 3;
  printf(" x = %d, y = %d, z = %d \n", x, y, z);
  {
       int x = 10;
       float y = 20;
       printf(" x = %d, y = %f, z = %d \n", x, y, z);
       {
             int z = 100;
             printf(" x = %d, y = %f, z = %d \n", x, y, z);
       }
  }
  return 0;
}

chevron_right


(A)

 x = 1, y = 2, z = 3
 x = 10, y = 20.000000, z = 3
 x = 1, y = 2, z = 100

(B) Compiler Error
(C)

 x = 1, y = 2, z = 3
 x = 10, y = 20.000000, z = 3
 x = 10, y = 20.000000, z = 100 

(D)

 x = 1, y = 2, z = 3
 x = 1, y = 2, z = 3
 x = 1, y = 2, z = 3


Answer: (C)

Explanation: See Scope rules in C

Quiz of this Question



My Personal Notes arrow_drop_up


Article Tags :
Practice Tags :


Be the First to upvote.


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.