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C | Structure & Union | Question 4

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Consider the following C declaration 
 

C

struct {
    short s[5];
    union {
         float y;
         long z;
    }u;
} t;

                    

Assume that objects of the type short, float and long occupy 2 bytes, 4 bytes and 8 bytes, respectively. The memory requirement for variable t, ignoring alignment considerations, is (GATE CS 2000)
 

(A)

22 bytes
 

(B)

14 bytes
 

(C)

18 bytes
 

(D)

10 bytes
 



Answer: (C)

Explanation:

Short array s[5] will take 10 bytes as size of short is 2 bytes. 

When we declare a union, memory allocated for the union is equal to memory needed for the largest member of it, and all members share this same memory space. Since u is a union, memory allocated to u will be max of float y(4 bytes) and long z(8 bytes). So, total size will be 18 bytes (10 + 8).
 



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Last Updated : 28 Jun, 2021
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