C | Structure & Union | Question 4

Consider the following C declaration

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struct { 
    short s[5];
    union { 
         float y; 
         long z; 
    }u; 
} t;

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Assume that objects of the type short, float and long occupy 2 bytes, 4 bytes and 8 bytes, respectively. The memory requirement for variable t, ignoring alignment considerations, is (GATE CS 2000)


(A) 22 bytes

(B) 14 bytes

(C) 18 bytes

(D) 10 bytes



 Answer: (C) 

Explanation: Short array s[5] will take 10 bytes as size of short is 2 bytes. 


        
          
          
          
        

            

When we declare a union, memory allocated for the union is equal to memory needed for the largest member of it, and all members share this same memory space.  Since u is a union, memory allocated to u will be max of float y(4 bytes) and long z(8 bytes). So, total size will be 18 bytes (10 + 8).

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