C | Structure & Union | Question 4

Consider the following C declaration

filter_none

edit
close

play_arrow

link
brightness_4
code

struct { 
    short s[5];
    union { 
         float y; 
         long z; 
    }u; 
} t;

chevron_right






                        filter_none








Assume that objects of the type short, float and long occupy 2 bytes, 4 bytes and 8 bytes, respectively. The memory requirement for variable t, ignoring alignment considerations, is (GATE CS 2000)


(A) 22 bytes

(B) 14 bytes

(C) 18 bytes

(D) 10 bytes



 Answer: (C) 

Explanation: Short array s[5] will take 10 bytes as size of short is 2 bytes. 


When we declare a union, memory allocated for the union is equal to memory needed for the largest member of it, and all members share this same memory space.  Since u is a union, memory allocated to u will be max of float y(4 bytes) and long z(8 bytes). So, total size will be 18 bytes (10 + 8).

Quiz of this Question


Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.



    

        My Personal Notes
        arrow_drop_up
    

    

        
        

            
            
        

    


Recommended Posts: