C | String | Question 9

Consider the following C program segment:

char p[20]; 
char *s = "string"
int length = strlen(s); 
int i; 
for (i = 0; i < length; i++) 
    p[i] = s[length — i]; 
printf("%s", p);

The output of the program is? (GATE CS 2004)
(A) gnirts
(B) gnirt
(C) string
(D) no output is printed

Answer: (D)

Explanation: Let us consider below line inside the for loop
p[i] = s[length — i];
For i = 0, p[i] will be s[6 — 0] and s[6] is ‘\0′
So p[0] becomes ‘\0’. It doesn’t matter what comes in p[1], p[2]….. as P[0] will not change for i >0. Nothing is printed if we print a string with first character ‘\0′

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