C | String | Question 9

Consider the following C program segment:

 char p[20]; 
 char *s = "string"; 
 int length = strlen(s); 
 int i; 
 for (i = 0; i < length; i++) 
     p[i] = s[length — i]; 
 printf("%s", p);

The output of the program is? (GATE CS 2004)
(A) gnirts
(B) gnirt
(C) string
(D) no output is printed

Answer: (D)

Explanation: Let us consider below line inside the for loop
p[i] = s[length — i];
For i = 0, p[i] will be s[6 — 0] and s[6] is ‘\0′
So p[0] becomes ‘\0’. It doesn’t matter what comes in p[1], p[2]….. as P[0] will not change for i >0. Nothing is printed if we print a string with first character ‘\0′

Quiz of this Question

GATE CS Corner    Company Wise Coding Practice

Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.

Recommended Posts:

0 Average Difficulty : 0/5.0
No votes yet.