What is the output of following program?
# include <stdio.h>
int main()
{
char str1[] = "GeeksQuiz" ;
char str2[] = { 'G' , 'e' , 'e' , 'k' , 's' , 'Q' , 'u' , 'i' , 'z' };
int n1 = sizeof (str1)/ sizeof (str1[0]);
int n2 = sizeof (str2)/ sizeof (str2[0]);
printf ( "n1 = %d, n2 = %d" , n1, n2);
return 0;
}
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(A) n1 = 10, n2 = 9
(B) n1 = 10, n2 = 10
(C) n1 = 9, n2 = 9
(D) n1 = 9, n2 = 10
Answer: (A)
Explanation: The size of str1 is 10 and size of str2 9.
When an array is initialized with string in double quotes, compiler adds a ‘\0’ at the end.
Last Updated :
02 Feb, 2013
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