C | String | Question 12

Output of following program

#include <stdio.h> 
int fun(char *p) 
{ 
    if (p == NULL || *p == '\0') return 0; 
    int current = 1, i = 1; 
    while (*(p+current)) 
    { 
        if (p[current] != p[current-1]) 
        { 
            p[i] = p[current]; 
            i++; 
        } 
        current++; 
    } 
    *(p+i)='\0'; 
    return i; 
} 
  
int main() 
{ 
    char str[] = "geeksskeeg"; 
    fun(str); 
    puts(str); 
    return 0; 
} 

(A) gekskeg
(B) geeksskeeg
(C) geeks
(D) Garbage Values

Answer: (A)

Explanation: The function mainly replaces more than once consecutive occurrences of a character with one one occurrence.

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