#include<stdio.h> int main()
{ typedef int *i;
int j = 10;
i *a = &j;
printf ( "%d" , **a);
return 0;
} |
(A) Compiler Error
(B) Garbage Value
(C) 10
(D) 0
Answer: (A)
Explanation: Compiler Error -> Initialization with incompatible pointer type.
The line typedef int *i makes i as type int *. So, the declaration of a means a is pointer to a pointer. The Error message may be different on different compilers.