C | Storage Classes and Type Qualifiers | Question 8

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#include<stdio.h>
int main()
{
  typedef int *i;
  int j = 10;
  i *a = &j;
  printf("%d", **a);
  return 0;
}

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(A) Compiler Error
(B) Garbage Value
(C) 10
(D) 0


Answer: (A)

Explanation: Compiler Error -> Initialization with incompatible pointer type.
The line typedef int *i makes i as type int *. So, the declaration of a means a is pointer to a pointer. The Error message may be different on different compilers.



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