#include<stdio.h>
int main()
{
typedef int *i;
int j = 10;
i *a = &j;
printf("%d", **a);
return 0;
}
|
(A) Compiler Error
(B) Garbage Value
(C) 10
(D) 0
Answer: (A)
Explanation: Compiler Error -> Initialization with incompatible pointer type.
The line typedef int *i makes i as type int *. So, the declaration of a means a is pointer to a pointer. The Error message may be different on different compilers.
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Last Updated :
09 Feb, 2013
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