Output of following program
#include <stdio.h>
int fun(int n)
{
static int s = 0;
s = s + n;
return (s);
}
int main()
{
int i = 10, x;
while (i > 0)
{
x = fun(i);
i--;
}
printf ("%d ", x);
return 0;
}
|
(A) 0
(B) 100
(C) 110
(D) 55
Answer: (D)
Explanation: Since s is static, different values of i are added to it one by one.
So final value of s is
s = i + (i-1) + (i-2) + … 3 + 2 + 1.
The value of s is i*(i+1)/2. For i = 10, s is 55.
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Last Updated :
28 Jun, 2021
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