# C# | Random.NextDouble() Method

• Last Updated : 01 May, 2019

The NextDouble() Method of System.Random class in C# is used to return a random floating-point number which is greater than or equal to 0.0, and less than 1.0.

Syntax:

`public virtual double NextDouble();`

Return Value: This method returns a double-precision floating point number which is greater than or equal to 0.0, and less than 1.0.

Below program illustrates the use of NextDouble() Method:

Example 1:

 `// C# program to illustrate the ``// Random.NextDouble() Method``using` `System;`` ` `class` `GFG {`` ` `    ``// Driver code``    ``public` `static` `void` `Main()``    ``{``        ``// Instantiate random number generator``        ``Random rand = ``new` `Random();`` ` `        ``// Print 10 random floating point numbers``        ``Console.WriteLine(``"Printing 10 random floating point numbers"``);``        ``for` `(``int` `i = 0; i < 10; i++)``            ``Console.WriteLine(``"{0} -> {1}"``, i, rand.NextDouble());``    ``}``}`

Output:

```Printing 10 random floating point numbers
0 -> 0.0227202852362396
1 -> 0.624568469647583
2 -> 0.0145442797870116
3 -> 0.646489209330869
4 -> 0.967497945748036
5 -> 0.839329582098559
6 -> 0.873648912121378
7 -> 0.16200648022909
8 -> 0.66018275761054
9 -> 0.0837694853934317
```

Example 2:

 `// C# program to illustrate the ``// Random.NextDouble() Method``using` `System;`` ` `class` `GFG {`` ` `    ``// Driver code``    ``public` `static` `void` `Main()``    ``{``        ``// Instantiate random number generator``        ``Random rand = ``new` `Random();`` ` `        ``// Instantiate an array of double``        ``double``[] a = ``new` `double``[10];`` ` `        ``// Store random floating point ``        ``// numbers in the array``        ``for` `(``int` `i = 0; i < 10; i++)``            ``a[i] = rand.NextDouble();`` ` `        ``// Print 10 random floating point numbers``        ``Console.WriteLine(``"Printing 10 random "``+``                      ``"floating point numbers"``);`` ` `        ``for` `(``int` `i = 0; i < 10; i++)``            ``Console.WriteLine(``"{0} -> {1}"``, i, a[i]);``    ``}``}`

Output:

```Printing 10 random floating point numbers
0 -> 0.853536825558886
1 -> 0.741455778359182
2 -> 0.496043408986201
3 -> 0.0975164361752181
4 -> 0.120282317567748
5 -> 0.57163705703413
6 -> 0.749181974562435
7 -> 0.684014179596684
8 -> 0.691246760865323
9 -> 0.888019556127498
```

Reference:

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