C# Program to Sort a List of Integers Using the LINQ OrderBy() Method
Given a list of integers, now our task is to sort the given list of integers. So we use the OrderBy() method of LINQ. This method is used to sort the elements in the collection in ascending order. This method is overloaded in two different ways:
- OrderBy<TSource, TKey>(IEnumerable<TSource>, Func<TSource, TKey>): It is used to sort the items of the given sequence in ascending order according to the key and performs a stable sort on the given sequence or list.
- OrderBy<TSource, TKey>(IEnumerable<TSource>, Func<TSource, TKey>, IComparer<TKey>): It is used to sort the items of the given sequence in ascending order by using a given comparer and also performs a stable sort on the given sequence.
Example:
Input : [90, 87, 34, 23, 22, 56, 21, 89]
Output : [21, 22, 23, 34, 56, 87, 89, 90]
Input : [10, 11, 2, 3, 18, 5,]
Output : [2, 3, 5, 10, 11, 18]
Approach:
1. Create and initialize a list of integer types. For example nums.
2. Sorting the list(named nums) using OrderBy() method
var result_set = nums.OrderBy(num => num);
3. Display the result using the foreach loop.
Example:
C#
using System;
using System.Linq;
using System.Collections.Generic;
class GFG{
static void Main( string [] args)
{
List< int > nums = new List< int >() { 50, 20, 40, 60, 33, 70 };
var result_set = nums.OrderBy(num => num);
Console.WriteLine( "Sorted in Ascending order:" );
foreach ( int value in result_set)
{
Console.Write(value + " " );
}
}
}
|
Output
Sorted in Ascending order:
20 33 40 50 60 70
Last Updated :
06 Dec, 2021
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