In C#, Math.Sqrt() is a Math class method which is used to calculate the square root of the specified number. Sqrt is a slower computation. It can be cached for a performance boost. Syntax:
public static double Sqrt(double d)
Parameter:
d: Number whose square root is to be calculated and type of this parameter is System.Double.
Return Type: This method returns the square root of d. If d is equal to NaN, NegativeInfinity, or PositiveInfinity, that value is returned. The return type of this method is System.Double. Examples:
Input : Math.Sqrt(81)
Output : 9
Input : Math.Sqrt(-81)
Output : NaN
Input : Math.Sqrt(0.09)
Output : 0.3
Input : Math.Sqrt(0)
Output : 0
Input : Math.Sqrt(-0)
Output : 0
Below C# programs illustrate the working of Math.Sqrt():
- Program 1: When the argument is positive double value then this method returns the square root of a given value.
csharp
using System;
class GFG {
public static void Main()
{
double x = 81;
Console.Write(Math.Sqrt(x));
}
}
|
- Program 2: When the argument is Negative, this method will return NaN.
csharp
using System;
class GFG {
public static void Main()
{
double x = -81;
Console.Write(Math.Sqrt(x));
}
}
|
- Program 3: When the argument is double value with decimal places, then this method will return the square root of a given value.
csharp
using System;
class GFG {
public static void Main()
{
double x = 0.09;
Console.Write(Math.Sqrt(x));
}
}
|
- Program 4: When the argument is positive or negative Zero, then it will return the result as Zero.
csharp
using System;
class GFG {
public static void Main()
{
double x = 0;
Console.WriteLine(Math.Sqrt(x));
double y = -0;
Console.Write(Math.Sqrt(y));
}
}
|
Note: If the value is too large then it gives the compile time error as error CS1021: Integral constant is too large. Reference: https://msdn.microsoft.com/en-us/library/system.math.sqrt
Last Updated :
06 Sep, 2022
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