Given an integer array of size **N**, the task is to traverse and print the elements in the array.

**Examples:**

Input:arr[] = {2, -1, 5, 6, 0, -3}

Output:2 -1 5 6 0 -3

Input:arr[] = {4, 0, -2, -9, -7, 1}

Output:4 0 -2 -9 -7 1

**Approach:-**

- Start a loop from
**0**to**N-1**, where**N**is the size of array.for(i = 0; i < N; i++)

- Access every element of array with help of
arr[index]

- Print the elements.
printf("%d ", arr[i])

Below is the implementation of the above approach:

## C

`// C program to traverse the array ` ` ` `#include <stdio.h> ` ` ` `// Function to traverse and print the array ` `void` `printArray(` `int` `* arr, ` `int` `n) ` `{ ` ` ` `int` `i; ` ` ` ` ` `printf` `(` `"Array: "` `); ` ` ` `for` `(i = 0; i < n; i++) { ` ` ` `printf` `(` `"%d "` `, arr[i]); ` ` ` `} ` ` ` `printf` `(` `"\n"` `); ` `} ` ` ` `// Driver program ` `int` `main() ` `{ ` ` ` `int` `arr[] = { 2, -1, 5, 6, 0, -3 }; ` ` ` `int` `n = ` `sizeof` `(arr) / ` `sizeof` `(arr[0]); ` ` ` ` ` `printArray(arr, n); ` ` ` ` ` `return` `0; ` `} ` |

*chevron_right*

*filter_none*

**Output:**

Array: 2 -1 5 6 0 -3

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