C Program to Store Information of Students Using Structure

Write a C program to store the information of Students using Structure. The information of each student to be stored is:

Each Student Record should have:
  Name
  Roll Number
  Age
  Total Marks

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

A structure is a user-defined data type in C/C++. A structure creates a data type that can be used to group items of possibly different types into a single type.

‘struct’ keyword is used to create the student structure as:

struct Student
{ 
   char* name; 
   int roll_number;
   int age;
   double total_marks;
};

Get the number of Students whose details are to be stored. Here we are taking 5 students for simplicity.
Create a variable of Student structure to access the records. Here it is taken as ‘student’
Get the data of n students and store it in student’s fields with the help of dot (.) operator
Syntax:
```
student[i].member = value;
```
After all the data is stored, print the records of each students using the dot (.) operator and loop.
Syntax:
```
student[i].member;
```

Below is the implementation of the above approach:

// C Program to Store Information 
// of Students Using Structure 
  
#include <stdio.h> 
#include <stdlib.h> 
#include <string.h> 
  
// Create the student structure 
struct Student { 
    char* name; 
    int roll_number; 
    int age; 
    double total_marks; 
}; 
  
// Driver code 
int main() 
{ 
    int i = 0, n = 5; 
  
    // Create the student's structure variable 
    // with n Student's records 
    struct Student student[n]; 
  
    // Get the students data 
    student[0].roll_number = 1; 
    student[0].name = "Geeks1"; 
    student[0].age = 12; 
    student[0].total_marks = 78.50; 
  
    student[1].roll_number = 5; 
    student[1].name = "Geeks5"; 
    student[1].age = 10; 
    student[1].total_marks = 56.84; 
  
    student[2].roll_number = 2; 
    student[2].name = "Geeks2"; 
    student[2].age = 11; 
    student[2].total_marks = 87.94; 
  
    student[3].roll_number = 4; 
    student[3].name = "Geeks4"; 
    student[3].age = 12; 
    student[3].total_marks = 89.78; 
  
    student[4].roll_number = 3; 
    student[4].name = "Geeks3"; 
    student[4].age = 13; 
    student[4].total_marks = 78.55; 
  
    // Print the Students information 
    printf("Student Records:\n\n"); 
    for (i = 0; i < n; i++) { 
        printf("\tName = %s\n", student[i].name); 
        printf("\tRoll Number = %d\n", student[i].roll_number); 
        printf("\tAge = %d\n", student[i].age); 
        printf("\tTotal Marks = %0.2f\n\n", student[i].total_marks); 
    } 
  
    return 0; 
} 

Output:

Student Records:

    Name = Geeks1
    Roll Number = 1
    Age = 12
    Total Marks = 78.50

    Name = Geeks5
    Roll Number = 5
    Age = 10
    Total Marks = 56.84

    Name = Geeks2
    Roll Number = 2
    Age = 11
    Total Marks = 87.94

    Name = Geeks4
    Roll Number = 4
    Age = 12
    Total Marks = 89.78

    Name = Geeks3
    Roll Number = 3
    Age = 13
    Total Marks = 78.55

My Personal Notes

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

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