C Program to Store Information of Students Using Structure
Write a C program to store the information of Students using Structure. The information of each student to be stored is:
Each Student Record should have: Name Roll Number Age Total Marks
- A structure is a user-defined data type in C/C++. A structure creates a data type that can be used to group items of possibly different types into a single type.
- ‘struct’ keyword is used to create the student structure as:
struct Student { char* name; int roll_number; int age; double total_marks; }; - Get the number of Students whose details are to be stored. Here we are taking 5 students for simplicity.
- Create a variable of Student structure to access the records. Here it is taken as ‘student’
- Get the data of n students and store it in student’s fields with the help of dot (.) operator
Syntax:student[i].member = value;
- After all the data is stored, print the records of each students using the dot (.) operator and loop.
Syntax:
student[i].member;
Below is the implementation of the above approach:
// C Program to Store Information// of Students Using Structure #include <stdio.h>#include <stdlib.h>#include <string.h> // Create the student structurestruct Student { char* name; int roll_number; int age; double total_marks;}; // Driver codeint main(){ int i = 0, n = 5; // Create the student's structure variable // with n Student's records struct Student student[n]; // Get the students data student[0].roll_number = 1; student[0].name = "Geeks1"; student[0].age = 12; student[0].total_marks = 78.50; student[1].roll_number = 5; student[1].name = "Geeks5"; student[1].age = 10; student[1].total_marks = 56.84; student[2].roll_number = 2; student[2].name = "Geeks2"; student[2].age = 11; student[2].total_marks = 87.94; student[3].roll_number = 4; student[3].name = "Geeks4"; student[3].age = 12; student[3].total_marks = 89.78; student[4].roll_number = 3; student[4].name = "Geeks3"; student[4].age = 13; student[4].total_marks = 78.55; // Print the Students information printf("Student Records:\n\n"); for (i = 0; i < n; i++) { printf("\tName = %s\n", student[i].name); printf("\tRoll Number = %d\n", student[i].roll_number); printf("\tAge = %d\n", student[i].age); printf("\tTotal Marks = %0.2f\n\n", student[i].total_marks); } return 0;} |
Output:
Student Records:
Name = Geeks1
Roll Number = 1
Age = 12
Total Marks = 78.50
Name = Geeks5
Roll Number = 5
Age = 10
Total Marks = 56.84
Name = Geeks2
Roll Number = 2
Age = 11
Total Marks = 87.94
Name = Geeks4
Roll Number = 4
Age = 12
Total Marks = 89.78
Name = Geeks3
Roll Number = 3
Age = 13
Total Marks = 78.55
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