C Program to print numbers from 1 to N without using semicolon?

How to print numbers from 1 to N without using any semicolon in C.

#include<stdio.h>
#define N 100

// Add your code here to print numbers from 1
// to N without using any semicolon

What code to add in above snippet such that it doesn’t contain semicolon and prints numbers from 1 to N?

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Method 1 (Recursive)

// A recursive C program to print all numbers from 1
// to N without semicoolon
#include<stdio.h>
#define N 10

int main(int num)
{
    if (num <= N && printf("%d ", num) && main(num + 1))
    {
    }     
}

Output:

1 2 3 4 5 6 7 8 9 10 

See this for complete run. Thanks to Utkarsh Trivedi for suggesting this solution.



Method 2 (Iterative)



// An iterative C program to print all numbers from 1
// to N without semicoolon
#include<stdio.h>
#define N 10

int main(int num, char *argv[])
{
while (num <= N && printf("%d ", num) && num++) 
{
} 
}

Output:

1 2 3 4 5 6 7 8 9 10 

See this for complete run. Thanks to Rahul Huria for suggesting this solution.

How do these solutions work?
main() function can receive arguments. The first argument is argument count whose value is 1 if no argument is passed to it. The first argument is always program name.

#include<stdio.h>

int main(int num, char *argv[])
{
   printf("num = %d\n", num);
   printf("argv[0] = %s ", argv[0]);
}

Output:

num = 1 
argv[0] = <file_name>

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Based on 38 vote(s)






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