# C program to Count the digits of a number

Given a number **N**, write a C program to find the count of digits in number** N**.

**Examples:**

Input:N = 12345Output:5Explanation:

The count of digit in 12345 = 5.

Input:N = 23451452Output:8Explanation:

The count of digits in 23451452 = 8.

**Approach:** Count of digits in a number can be found efficiently in few steps:

- Remove the last digit of number by dividing it with 10.
- Increment the
**count**of digit by**1**. - Keep repeating steps 1 and 2 until the value of
**N**becomes**0**. In this case, there will be no more digit left in the number to count

## C

`// C Program to find count of` `// digits in a number` ` ` `#include <stdio.h>` ` ` `// Find the count of digits` `int` `findCount(` `int` `n)` `{` ` ` `int` `count = 0;` ` ` ` ` `// Remove last digit from number` ` ` `// till number is 0` ` ` `while` `(n != 0) {` ` ` ` ` `//Increment count` ` ` `count++;` ` ` `n /= 10;` ` ` `}` ` ` ` ` `// return the count of digit` ` ` `return` `count;` `}` ` ` `// Driver program` `int` `main()` `{` ` ` `int` `n = 98562;` ` ` `printf` `(` `"Count of digits in %d = %d\n"` `,` ` ` `n, findCount(n));` ` ` `return` `0;` `}` |

**Output:**

Count of digits in 98562 = 5

* Time complexity: O(D)*, where D is the count of digits in number N.

**Auxiliary Space complexity:**O(1)