# C program to Count the digits of a number

Given a number N, write a C program to find the count of digits in number N.

Examples:

Input: N = 12345
Output: 5
Explanation:
The count of digit in 12345 = 5.

Input: N = 23451452
Output: 8
Explanation:
The count of digits in 23451452 = 8.

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: Count of digits in a number can be found efficiently in few steps:

1. Remove the last digit of number by dividing it with 10.
2. Increment the count of digit by 1.
3. Keep repeating steps 1 and 2 until the value of N becomes 0. In this case, there will be no more digit left in the number to count

## C

 `// C Program to find count of ` `// digits in a number ` ` `  `#include ` ` `  `// Find the count of digits ` `int` `findCount(``int` `n) ` `{ ` `    ``int` `count = 0; ` ` `  `    ``// Remove last digit from number ` `    ``// till number is 0 ` `    ``while` `(n != 0) { ` ` `  `  ``//Increment count ` `        ``count++; ` `        ``n /= 10; ` `    ``} ` ` `  `    ``// return the count of digit ` `    ``return` `count; ` `} ` ` `  `// Driver program ` `int` `main() ` `{ ` `    ``int` `n = 98562; ` `    ``printf``(``"Count of digits in %d = %d\n"``, ` ` ``n, findCount(n)); ` `    ``return` `0; ` `} `

Output:

```Count of digits in 98562 = 5
```

Time complexity: O(D), where D is the count of digits in number N.
Auxiliary Space complexity: O(1)

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