C program to count number of vowels and consonants in a String

Given a string and write a C program to count the number of vowels and consonants in this string. Examples:

Input: str = "geeks for geeks"
Output:
Vowels: 5
Consonants: 8

Input: str = "abcdefghijklmnopqrstuvwxyz"
Output:
Vowels: 5
Consonants: 21

Approach:

• Take the string as input
• Take each character from this string to check
• If this character is a vowel, increment the count of vowels
• Else increment the count of consonants.
• Print the total count of vowels and consonants in the end.

Below is the implementation of the above approach: 

C

// C program to count the number of
// vowels and consonants in a string

#include <stdio.h>

// Function to count number
// of vowels and consonant
void count_vowels_and_consonant(char* str)
{
    // Declare the variable vowels and consonant
    int vowels = 0, consonants = 0;

    int i;
    char ch;

    // Take each character from this string to check
    for (i = 0; str[i] != '\0'; i++) {

        ch = str[i];

        // If this character is a vowel,
        // increment the count of vowels
        if (ch == 'a' || ch == 'e'
            || ch == 'i' || ch == 'o'
            || ch == 'u' || ch == 'A'
            || ch == 'E' || ch == 'I'
            || ch == 'O' || ch == 'U')
            vowels++;

        // If this character is a space
        // skip it
        else if (ch == ' ')
            continue;

        else
            // Else increment the count of consonants
            consonants++;
    }

    // Print the total count of vowels and consonants
    printf("\nVowels: %d", vowels);
    printf("\nConsonants: %d", consonants);
}

// Driver function.
int main()
{
    char* str = "geeks for geeks";
    printf("String: %s", str);

    count_vowels_and_consonant(str);

    return 0;
}

Output:

String: geeks for geeks
Vowels: 5
Consonants: 8

Time Complexity: O(1)

Auxiliary Space: O(1)