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C program to check if a given year is leap year using Conditional operator
  • Last Updated : 16 Jan, 2020

Given an integer which represents the year, the task is to check if this is a leap year, with the help of Ternary Operator.

A year is a leap year if the following conditions are satisfied:

  1. Year is multiple of 400.
  2. Year is multiple of 4 and not multiple of 100.

Following is pseudo code

if year is divisible by 400 then is_leap_year
else if year is divisible by 100 then not_leap_year
else if year is divisible by 4 then is_leap_year
else not_leap_year

Below is the implementation of the above approach:




// C program to check if a given
// year is a leap year or not
  
#include <stdbool.h>
#include <stdio.h>
  
bool checkYear(int n)
{
  
    return (n % 400 == 0)
               ? true
               : (n % 4 == 0)
                     ? (n % 100 != 0)
                     : false
                           ? true
                           : false;
}
  
// Driver code
int main()
{
    int year = 2000;
  
    checkYear(year)
        ? printf("Leap Year")
        : printf("Not a Leap Year");
  
    return 0;
}
Output:
Leap Year

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