C program to check if a given year is leap year using Conditional operator

Given an integer that represents the year, the task is to check if this is a leap year, with the help of Ternary Operator. A year is a leap year if the following conditions are satisfied:

1. The year is multiple of 400.
2. The year is a multiple of 4 and not a multiple of 100.

Following is pseudo-code

if year is divisible by 400 then is_leap_year
else if year is divisible by 100 then not_leap_year
else if year is divisible by 4 then is_leap_year
else not_leap_year

Below is the implementation of the above approach: 

C

// C program to check if a given
// year is a leap year or not

#include <stdbool.h>
#include <stdio.h>

bool checkYear(int n)
{

    return (n % 400 == 0)
               ? true
               : (n % 4 == 0) ? (n % 100 != 0)
                              : false ? true : false;
}

// Driver code
int main()
{
    int year = 2000;

    checkYear(year) ? printf("Leap Year")
                    : printf("Not a Leap Year");

    return 0;
}

Output

Leap Year

Time Complexity: O(1), As only constant time operations are performed.
Auxiliary Space: O(1), As constant extra space is used.