C Program to print Floyd's triangle

C Program to print Floyd’s triangle

Difficulty Level : Basic
Last Updated : 09 Oct, 2019

Floyd’s triangle is a triangle with first natural numbers.

1
2     3
4     5     6
7     8     9     10
11     12     13     14     15

Recommended: Please solve it on “PRACTICE” first, before moving on to the solution.

Following program prints Floyd’s triangle with n lines.

C++

#include <bits/stdc++.h> 
using namespace std; 
  
void printFloydTriangle(int n)  
{  
    int i, j, val = 1;  
    for (i = 1; i <= n; i++)  
    {  
        for (j = 1; j <= i; j++)  
            cout << val++ << " ";  
        cout << endl;  
    }  
}  
  
// Driver Code 
int main()  
{  
    printFloydTriangle(6);  
    return 0;  
}  
  
// This is code is contributed  
// by rathbhupendra 

C

// Without using a temporary variable and with only one loop 
#include<stdio.h> 
void floyd(n){ 
    int i,j=1; 
    for (i=1;i<=(n*(n+1))/2;i++){ 
        printf("%d ",i); 
        if(i==(j*(j+1))/2){ 
            printf("\n"); 
            j++; 
        } 
    } 
} 
  
int main(){ 
    floyd(6); 
} 
  
//This code is contributed by Vishal B 

Java

// Java program to print 
// Floyd's triangle 
class GFG 
{ 
    static void printFloydTriangle(int n) 
    { 
        int i, j, val = 1; 
        for (i = 1; i <= n; i++) 
        { 
            for (j = 1; j <= i; j++) 
            { 
                System.out.print(val + " "); 
                val++; 
            } 
            System.out.println(); 
                  
        } 
    } 
          
    // Driver Code 
    public static void main(String[] args)  
    { 
        printFloydTriangle(6); 
    } 
} 

Python3

# Python3 program to print 
# Floyd's triangle 
def loydTriangle(n): 
  
    val = 1
    for i in range(1, n + 1): 
  
        for j in range(1, i + 1): 
            print(val, end = " ") 
            val += 1
          
        print("") 
  
loydTriangle(6) 
  
# This code is contributed by 
# Smitha Dinesh Semwal 

C#

// C# program to print 
// Floyd's triangle 
using System; 
  
class GFG 
{ 
    static void printFloydTriangle(int n) 
    { 
        int i, j, val = 1; 
        for (i = 1; i <= n; i++) 
        { 
            for (j = 1; j <= i; j++) 
            { 
                Console.Write(val + " "); 
                val++; 
            } 
            Console.WriteLine(); 
        } 
    } 
          
    // Driver Code 
    public static void Main()  
    { 
        printFloydTriangle(6); 
    } 
} 

PHP

<?php 
// PHP code to print Floyd's Triangle 
  
// Function to display Floyd's Triangle 
function FloydsTriangle($n) 
{ 
    $val = 1; 
      
    // loop for number of lines 
    for($i = 1; $i <= $n; $i++) 
    { 
        // loop for number of elements 
        // in each line 
        for($j = 1; $j <= $i; $j++) 
        { 
            print($val." "); 
            $val++; 
        } 
        print("\n"); 
    } 
} 
  
// Driver's Code 
$n = 6; 
FloydsTriangle($n); 
  
// This code is contributed by akash7981 
?>  

Output:

1
2 3
4 5 6
7 8 9 10
11 12 13 14 15
16 17 18 19 20 21

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Recommended: Please solve it on “PRACTICE” first, before moving on to the solution.

C++

C

Java

Python3

C#

PHP