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C# Program For Printing Reverse Of A Linked List Without Actually Reversing

  • Last Updated : 14 Dec, 2021

Given a linked list, print reverse of it using a recursive function. For example, if the given linked list is 1->2->3->4, then output should be 4->3->2->1.
Note that the question is only about printing the reverse. To reverse the list itself see this 
Difficulty Level: Rookie 



  1. call print reverse for head->next
  2. print head->data



// C# program to print reverse 
// of a linked list
using System;
public class LinkedList
    // Head of list
    Node head; 
    // Linked list Node
    class Node
        public int data;
        public Node next;
        public Node(int d) 
            data = d; next = null;
    // Function to print reverse 
    // of linked list 
    void printReverse(Node head)
        if (head == null) return;
        // print list of head node
        // After everything else is printed
        Console.Write( + " ");
    // Utility Functions 
    // Inserts a new Node at front 
    // of the list. 
    public void push(int new_data)
        /* 1 & 2: Allocate the Node &
                  Put in the data*/
        Node new_node = new Node(new_data);
        // 3. Make next of new Node as head = head;
        // 4. Move the head to point to 
        // new Node 
        head = new_node;
    // Driver code
    public static void Main(String []args)
        // Let us create linked list 1->2->3->4
        LinkedList llist = new LinkedList();
// This code is contributed by Rajput-Ji 


4 3 2 1

Time Complexity: O(n)

Please refer complete article on Print reverse of a Linked List without actually reversing for more details!

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