C Program for Fibonacci numbers

• Last Updated : 04 Dec, 2018

The Fibonacci numbers are the numbers in the following integer sequence.

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, ……..

In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the recurrence relation

Fn = Fn-1 + Fn-2

with seed values

F0 = 0 and F1 = 1.

C

 // Fibonacci Series using Recursion#include int fib(int n){    if (n <= 1)        return n;    return fib(n - 1) + fib(n - 2);}  int main(){    int n = 9;    printf("%d", fib(n));    getchar();    return 0;}
Output:
34

Time Complexity: T(n) = T(n-1) + T(n-2) which is exponential.
We can observe that this implementation does a lot of repeated work (see the following recursion tree). So this is a bad implementation for nth Fibonacci number.

fib(5)
/
fib(4)                fib(3)
/                      /
fib(3)      fib(2)         fib(2)    fib(1)
/             /           /
fib(2)   fib(1)  fib(1) fib(0) fib(1) fib(0)
/
fib(1) fib(0)

Extra Space: O(n) if we consider the function call stack size, otherwise O(1).

Method 2 ( Use Dynamic Programming )
We can avoid the repeated work done is the method 1 by storing the Fibonacci numbers calculated so far.

C

 // Fibonacci Series using Dynamic Programming#include   int fib(int n){    /* Declare an array to store Fibonacci numbers. */    int f[n + 1];    int i;      /* 0th and 1st number of the series are 0 and 1*/    f = 0;    f = 1;      for (i = 2; i <= n; i++) {        /* Add the previous 2 numbers in the series         and store it */        f[i] = f[i - 1] + f[i - 2];    }      return f[n];}  int main(){    int n = 9;    printf("%d", fib(n));    getchar();    return 0;}
Output:
34

Time Complexity: O(n)
Extra Space: O(n)

Method 3 ( Space Optimized Method 2 )
We can optimize the space used in method 2 by storing the previous two numbers only because that is all we need to get the next Fibonacci number in series.

C/C++

 // Fibonacci Series using Space Optimized Method#include int fib(int n){    int a = 0, b = 1, c, i;    if (n == 0)        return a;    for (i = 2; i <= n; i++) {        c = a + b;        a = b;        b = c;    }    return b;}  int main(){    int n = 9;    printf("%d", fib(n));    getchar();    return 0;}
Output:
34

Please refer complete article on Program for Fibonacci numbers for more details!

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