C Program to Check if all digits of a number divide it

Given a number n, find whether all digits of n divide it or not.

Examples:

Input : 128
Output : Yes
128 % 1 == 0, 128 % 2 == 0, and 128 % 8 == 0.

Input : 130
Output : No

We want to test whether each digit is non-zero and divides the number. For example, with 128, we want to test d != 0 && 128 % d == 0 for d = 1, 2, 8. To do that, we need to iterate over each digit of the number.



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// CPP program to check the number
// is divisible by all digits are not.
#include <bits/stdc++.h>
using namespace std;
  
// Function to check the divisibility
// of the number by its digit.
bool checkDivisibility(int n, int digit)
{
    // If the digit divides the number
    // then return true else return false.
    return (digit != 0 && n % digit == 0);
}
  
// Function to check if all digits
// of n divide it or not
bool allDigitsDivide(int n)
{
    int temp = n;
    while (temp > 0) {
  
        // Taking the digit of the
        // number into digit var.
        int digit = n % 10;
        if (!(checkDivisibility(n, digit)))
            return false;
  
        temp /= 10;
    }
    return true;
}
  
// Driver function
int main()
{
    int n = 128;
    if (allDigitsDivide(n))
        cout << "Yes";
    else
        cout << "No";
    return 0;
}

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Output:

Yes

Please refer complete article on Check if all digits of a number divide it for more details!



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