# C program to calculate the value of nPr

nPr represents n permutation r and value of nPr is (n!) / (n-r)!.

`#include<stdio.h> ` ` ` `int` `fact(` `int` `n) ` `{ ` ` ` `if` `(n <= 1) ` ` ` `return` `1; ` ` ` `return` `n*fact(n-1); ` `} ` ` ` `int` `nPr(` `int` `n, ` `int` `r) ` `{ ` ` ` `return` `fact(n)/fact(n-r); ` `} ` ` ` `int` `main() ` `{ ` ` ` `int` `n, r; ` ` ` `printf` `(` `"Enter n: "` `); ` ` ` `scanf` `(` `"%d"` `, &n); ` ` ` ` ` `printf` `(` `"Enter r: "` `); ` ` ` `scanf` `(` `"%d"` `, &r); ` ` ` ` ` `printf` `(` `"%dP%d is %d"` `, n, r, nPr(n, r)); ` ` ` ` ` `return` `0; ` `}` |

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Enter n: 5 Enter r: 2 5P2 is 20

Please refer Permutation Coefficient for efficient methods to compute nPr.

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