C | Pointer Basics | Question 4

Consider a compiler where int takes 4 bytes, char takes 1 byte and pointer takes 4 bytes.

#include <stdio.h>

int main()
{
    int arri[] = {1, 2 ,3};
    int *ptri = arri;

    char arrc[] = {1, 2 ,3};
    char *ptrc = arrc;

    printf(\"sizeof arri[] = %d \", sizeof(arri));
    printf(\"sizeof ptri = %d \", sizeof(ptri));

    printf(\"sizeof arrc[] = %d \", sizeof(arrc));
    printf(\"sizeof ptrc = %d \", sizeof(ptrc));

    return 0;
}

(A)

sizeof arri[] = 3 sizeof ptri = 4 sizeof arrc[] = 3 sizeof ptrc = 4

(B)

sizeof arri[] = 12 sizeof ptri = 4 sizeof arrc[] = 3 sizeof ptrc = 1

(C)

sizeof arri[] = 3 sizeof ptri = 4 sizeof arrc[] = 3 sizeof ptrc = 1

(D)

sizeof arri[] = 12 sizeof ptri = 4 sizeof arrc[] = 3 sizeof ptrc = 4

Answer

Please comment below if you find anything wrong in the above post
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