Output of following program?
# include <stdio.h> void fun( int *ptr)
{ *ptr = 30;
} int main()
{ int y = 20;
fun(&y);
printf ( "%d" , y);
return 0;
} |
(A) 20
(B) 30
(C) Compiler Error
(D) Runtime Error
Answer: (B)
Explanation: The function fun() expects a pointer ptr to an integer (or an address of an integer). It modifies the value at the address ptr. The dereference operator * is used to access the value at an address. In the statement ‘*ptr = 30’, value at address ptr is changed to 30. The address operator & is used to get the address of a variable of any data type. In the function call statement ‘fun(&y)’, address of y is passed so that y can be modified using its address.