C | Pointer Basics | Question 1
What is the output of following program?
# include <stdio.h>void fun(int x){ x = 30;} int main(){ int y = 20; fun(y); printf("%d", y); return 0;} |
(A) 30
(B) 20
(C) Compiler Error
(D) Runtime Error
Answer: (B)
Explanation: Parameters are always passed by value in C. Therefore, in the above code, value of y is not modified using the function fun(). So how do we modify the value of a local variable of a function inside another function. Pointer is the solution to such problems. Using pointers, we can modify a local variable of a function inside another function. See the next question.
Note that everything is passed by value in C. We only get the effect of pass by reference using pointers.
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