C | Pointer Basics | Question 16

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#include <stdio.h>
int main()
{
    int arr[] = {1, 2, 3, 4, 5};
    int *p = arr;
    ++*p;
    p += 2;
    printf("%d", *p);
    return 0;
}
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(A) 2
(B) 3
(C) 4
(D) Compiler Error

Answer: (B)
Explanation: The expression ++*p is evaluated as “++(*p)” . So it increments the value of first element of array (doesn’t change the pointer p).

When p += 2 is done, p is changed to point to third element of array.
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