#include <stdio.h> int main()
{ int arr[] = {1, 2, 3, 4, 5};
int *p = arr;
++*p;
p += 2;
printf ( "%d" , *p);
return 0;
} |
(A) 2
(B) 3
(C) 4
(D) Compiler Error
Answer: (B)
Explanation: The expression ++*p is evaluated as “++(*p)” . So it increments the value of first element of array (doesn’t change the pointer p).
When p += 2 is done, p is changed to point to third element of array.
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