C | Pointer Basics | Question 16
#include <stdio.h> int main() { int arr[] = {1, 2, 3, 4, 5}; int *p = arr; ++*p; p += 2; printf("%d", *p); return 0; } |
chevron_right
filter_none
(A) 2
(B) 3
(C) 4
(D) Compiler Error
Answer: (B)
Explanation: The expression ++*p is evaluated as “++(*p)” . So it increments the value of first element of array (doesn’t change the pointer p).
When p += 2 is done, p is changed to point to third element of array.
Quiz of this Question
Recommended Posts:
- C | Pointer Basics | Question 17
- C | Pointer Basics | Question 6
- C | Pointer Basics | Question 15
- C | Pointer Basics | Question 7
- C | Pointer Basics | Question 8
- C | Pointer Basics | Question 10
- C | Pointer Basics | Question 11
- C | Pointer Basics | Question 12
- C | Pointer Basics | Question 13
- C | Pointer Basics | Question 17
- C | Pointer Basics | Question 3
- C | Pointer Basics | Question 17
- C | Pointer Basics | Question 4
- C | Pointer Basics | Question 14
- C | Pointer Basics | Question 1
