C | Pointer Basics | Question 16
#include <stdio.h> int main() { int arr[] = {1, 2, 3, 4, 5}; int *p = arr; ++*p; p += 2; printf("%d", *p); return 0; } |
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(A) 2
(B) 3
(C) 4
(D) Compiler Error
Answer: (B)
Explanation: The expression ++*p is evaluated as “++(*p)” . So it increments the value of first element of array (doesn’t change the pointer p).
When p += 2 is done, p is changed to point to third element of array.
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