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C | Operators | Question 7

  • Difficulty Level : Medium
  • Last Updated : 28 Jun, 2021

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#include <stdio.h>
int main()
    int i = 5, j = 10, k = 15;
    printf("%d ", sizeof(k /= i + j));
    printf("%d", k);
    return 0;

Assume size of an integer as 4 bytes. What is the output of above program?
(A) 4 1
(B) 4 15
(C) 2 1
(D) Compile-time error

Answer: (B)

Explanation: The main theme of the program lies here: sizeof(k /= i + j). An expression doesn’t get evaluated inside sizeof operator. sizeof operator returns sizeof(int) because the result of expression will be an integer. As the expression is not evaluated, value of k will not be changed.

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