C | Operators | Question 10
What is the output of following program?
a = 1;
b = 1;
c = a || --b;
d = a-- && --b;
"a = %d, b = %d, c = %d, d = %d"
, a, b, c, d);
(A) a = 0, b = 1, c = 1, d = 0
(B) a = 0, b = 0, c = 1, d = 0
(C) a = 1, b = 1, c = 1, d = 1
(D) a = 0, b = 0, c = 0, d = 0
Explanation: Let us understand the execution line by line.
Initial values of a and b are 1.
// Since a is 1, the expression --b
// is not executed because
// of the short-circuit property
// of logical or operator
// So c becomes 1, a and b remain 1
int c = a || --b;
// The post decrement operator --
// returns the old value in current expression
// and then updates the value. So the
// value of expression a-- is 1. Since the
// first operand of logical and is 1,
// shortcircuiting doesn't happen here. So
// the expression --b is executed and --b
// returns 0 because it is pre-increment.
// The values of a and b become 0, and
// the value of d also becomes 0.
int d = a-- && --b;
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