C | Operators | Question 1
#include "stdio.h" int main() { int x, y = 5, z = 5; x = y == z; printf("%d", x); getchar(); return 0; }
(A) 0
(B) 1
(C) 5
(D) Compiler Error
Answer: (B)
Explanation: The crux of the question lies in the statement x = y==z. The operator == is executed before = because precedence of comparison operators (<=, >= and ==) is higher than assignment operator =.
The result of a comparison operator is either 0 or 1 based on the comparison result. Since y is equal to z, value of the expression y == z becomes 1 and the value is assigned to x via the assignment operator.
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