#include "stdio.h"
int main() 
{ 
  int x, y = 5, z = 5; 
  x = y == z; 
  printf("%d", x); 
  
  getchar(); 
  return 0; 
}

(A) 0
(B) 1
(C) 5
(D) Compiler Error

Answer: (B)

Explanation: The crux of the question lies in the statement x = y==z. The operator == is executed before = because precedence of comparison operators (<=, >= and ==) is higher than assignment operator =.
The result of a comparison operator is either 0 or 1 based on the comparison result. Since y is equal to z, value of the expression y == z becomes 1 and the value is assigned to x via the assignment operator.