Skip to content
Related Articles

Related Articles

C++ | Operator Overloading | Question 7
  • Last Updated : 20 Sep, 2013

Output of following program?




#include <iostream>
using namespace std;
class Test2
{
    int y;
};
  
class Test
{
    int x;
    Test2 t2;
public:
    operator Test2 ()  { return t2; }
    operator int () { return x; }
};
  
void fun ( int x) { cout << "fun(int) called"; }
void fun ( Test2 t ) { cout << "fun(Test 2) called"; }
  
int main()
{
    Test t;
    fun(t);
    return 0;
}


(A) fun(int) called
(B) fun(Test 2) called
(C) Compiler Error: Ambiguous call to fun()


Answer: (C)

Explanation: The class Test has two conversion operators overloaded, int and Test2. And there are two fun() for int and Test2.

Quiz of this Question

Attention reader! Don’t stop learning now. Get hold of all the important C++ Foundation and STL concepts with the C++ Foundation and STL courses at a student-friendly price and become industry ready.

My Personal Notes arrow_drop_up
Recommended Articles
Page :