Open In App

C | Macro & Preprocessor | Question 6

Like Article
Like
Save
Share
Report




#include <stdio.h>
#define square(x) x*x
int main()
{
  int x;
  x = 36/square(6);
  printf("%d", x);
  return 0;
}


(A) 1
(B) 36
(C) 0
(D) Compiler Error


Answer: (B)

Explanation: Preprocessor replaces square(6) by 6*6 and the expression becomes x = 36/6*6 and value of x is calculated as 36. Note that the macro will also fail for expressions “x = square(6-2)”

If we want correct behavior from macro square(x), we should declare the macro as

#define square(x) ((x)*(x))  


Quiz of this Question


Last Updated : 28 Jun, 2021
Like Article
Save Article
Previous
Next
Share your thoughts in the comments
Similar Reads