C | Macro & Preprocessor | Question 6
#include <stdio.h>
#define square(x) x*x
int main()
{
int x;
x = 36/square(6);
printf ( "%d" , x);
return 0;
}
|
(A) 1
(B) 36
(C) 0
(D) Compiler Error
Answer: (B)
Explanation: Preprocessor replaces square(6) by 6*6 and the expression becomes x = 36/6*6 and value of x is calculated as 36. Note that the macro will also fail for expressions “x = square(6-2)”
If we want correct behavior from macro square(x), we should declare the macro as
#define square(x) ((x)*(x))
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Last Updated :
28 Jun, 2021
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