C | Macro & Preprocessor | Question 4

#include <stdio.h>
#define X 3
#if !X
    printf("Geeks");
#else
    printf("Quiz");

#endif
int main()
{
        return 0;
}

(A) Geeks
(B) Quiz
(C) Compiler Error
(D) Runtime Error


Answer: (C)

Explanation: A program is converted to executable using following steps

1) Preprocessing

2) C code to object code conversion

3) Linking

The first step processes macros. So the code is converted to following after the preprocessing step.

printf("Quiz");
int main()
{
        return 0;
}

The above code produces error because printf() is called outside main. The following program works fine and prints “Quiz”

#include 
#define X 3

int main()
{
#if !X
    printf("Geeks");
#else
    printf("Quiz");

#endif
    return 0;
}

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