C | Loops & Control Structure | Question 5
Predict the output of the below program:
#include <stdio.h> #define EVEN 0 #define ODD 1 int main() { int i = 3; switch (i & 1) { case EVEN: printf("Even"); break; case ODD: printf("Odd"); break; default: printf("Default"); } return 0; } |
(A) Even
(B) Odd
(C) Default
(D) Compile-time error
Answer: (B)
Explanation: The expression i & 1 returns 1 if the rightmost bit is set and returns 0 if the rightmost bit is not set. As all odd integers have their rightmost bit set, the control goes to the block labeled ODD.
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