C | Loops & Control Structure | Question 5

Predict the output of the below program:

#include <stdio.h> 
#define EVEN 0 
#define ODD 1 
int main() 
{ 
    int i = 3; 
    switch (i & 1) 
    { 
        case EVEN: printf("Even"); 
                break; 
        case ODD: printf("Odd"); 
                break; 
        default: printf("Default"); 
    } 
    return 0; 
} 

(A) Even
(B) Odd
(C) Default
(D) Compile-time error

Answer: (B)

Explanation: The expression i & 1 returns 1 if the rightmost bit is set and returns 0 if the rightmost bit is not set. As all odd integers have their rightmost bit set, the control goes to the block labeled ODD.

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