C | Loops & Control Structure | Question 16
What is the output of the following program?
#include <stdio.h> int main() { char check = 'a' ; switch (check) { case 'a' || 1: printf ( "Geeks " ); case 'b' || 2: printf ( "Quiz " ); break ; default : printf ( "GeeksQuiz" ); } return 0; } |
(A) Geeks
(B) Geeks Quiz
(C) Geeks Quiz GeeksQuiz
(D) Compile-time error
Answer: (D)
Explanation: An expression gets evaluated in a case label. Both the cases used are evaluated to 1(true). So compile-time error: duplicate case value is flashed as duplicated cases are not allowed.
Quiz of this Question
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