Output of following C program?
#include<stdio.h>
int main()
{
int i = 0;
for (printf("1st\n"); i < 2 && printf("2nd\n"); ++i && printf("3rd\n"))
{
printf("*\n");
}
return 0;
}
|
(A) 1st
2nd
*
3rd
2nd
*
(B) 1st
2nd
*
3rd
2nd
*
3rd
(C) 1st
2nd
3rd
*
2nd
3rd
(D) 1st
2nd
3rd
*
1st
2nd
3rd
Answer: (B)
Explanation: It is just one by one execution of statements in for loop.
a) The initial statement is executed only once.
b) The second condition is printed before ‘*’ is printed. The second statement also has short circuiting logical && operator which prints the second part only if ‘i’ is smaller than 2
b) The third statement is printed after ‘*’ is printed. This also has short circuiting logical && operator which prints the second part only if ‘++i’ is not zero.